What is the inverse of+sqrt(x^2-7x) ?

The inverse of+sqrt(x^2-7x) is (7+sqrt(49+4x^2))/2 ,(7-sqrt(49+4x^2))/2

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inverse of+sqrt(x^2-7x)

inverse

+ x^{2} - 7 x

\frac{7 + 49 + 4 x ^{2}}{2}, \frac{7 - 49 + 4 x ^{2}}{2}

Solution steps

y = x^{2} - 7 x

Replace

x

with

y

x = y^{2} - 7 y

Solve for

y, x = + y^{2} - 7 y

\frac{7 + 49 + 4 x ^{2}}{2}, \frac{7 - 49 + 4 x ^{2}}{2}

f (x) = ln (x) + 1, x > 1

5 x^{4} + 2 x^{2}

\frac{1}{x ^{11}}

y = \frac{x - 2}{5 x + 7}

231 - 1

What is the inverse of+sqrt(x^2-7x) ?
The inverse of+sqrt(x^2-7x) is (7+sqrt(49+4x^2))/2 ,(7-sqrt(49+4x^2))/2