What is the inverse of f(x)=4+\sqrt[5]{3x+1} ?

The inverse of f(x)=4+\sqrt[5]{3x+1} is (x^5-20x^4+160x^3-640x^2+1280x-1025)/3

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inverse of f(x)=4+\sqrt[5]{3x+1}

inverse

\frac{x ^{5} - 20 x ^{4} + 160 x ^{3} - 640 x ^{2} + 1280 x - 1025}{3}

Solution steps

Replace

x

with

y

Solve for

\frac{x ^{5} - 20 x ^{4} + 160 x ^{3} - 640 x ^{2} + 1280 x - 1025}{3}

0.3234 ln (x) + 0.4893

226

f (x) = - e^{- 30 x} + 1

\frac{3 X - 1}{2 X + 4}

f (x) = - \frac{4}{84}

What is the inverse of f(x)=4+\sqrt[5]{3x+1} ?
The inverse of f(x)=4+\sqrt[5]{3x+1} is (x^5-20x^4+160x^3-640x^2+1280x-1025)/3