What is the inverse of P(t)=(1000)/(1+9e^{-t)} ?

The inverse of P(t)=(1000)/(1+9e^{-t)} is -ln((1000-t)/(9t))

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inverse of P(t)=(1000)/(1+9e^{-t)}

inverse

P (t) = \frac{1000}{1 + 9 e ^{- t}}

- ln (\frac{1000 - t}{9 t})

Solution steps

y = \frac{1000}{1 + 9 e ^{- t}}

Replace

t

with

y

t = \frac{1000}{1 + 9 e ^{- y}}

Solve for

y, t = \frac{1000}{1 + 9 e ^{- y}}

- ln (\frac{1000 - t}{9 t})

f (x) = \frac{5 x + 2}{3 x + 3}

f (x) = (4 x \cdot x^{1} - 9 + 5 x)^{2}

f (x) = 60 - 0.25 y

f (x) = 51 + 2.4 (x - 61)

tan (0.011 x)

What is the inverse of P(t)=(1000)/(1+9e^{-t)} ?
The inverse of P(t)=(1000)/(1+9e^{-t)} is -ln((1000-t)/(9t))