What is the inverse of (10)/((t+16)(t+25)) ?

The inverse of (10)/((t+16)(t+25)) is (-41t+sqrt(81t^2+40t))/(2t),(-41t-sqrt(81t^2+40t))/(2t)

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inverse of (10)/((t+16)(t+25))

inverse

\frac{10}{( t + 16 ) ( t + 25 )}

\frac{- 41 t + 81 t ^{2} + 40 t}{2 t}, \frac{- 41 t - 81 t ^{2} + 40 t}{2 t}

Solution steps

y = \frac{10}{( t + 16 ) ( t + 25 )}

Replace

t

with

y

t = \frac{10}{( y + 16 ) ( y + 25 )}

Solve for

y, t = \frac{10}{( y + 16 ) ( y + 25 )}

\frac{- 41 t + 81 t ^{2} + 40 t}{2 t}, \frac{- 41 t - 81 t ^{2} + 40 t}{2 t}

f (x) = - x^{2} - 4, x < 0

y (X) = \frac{2 X + 3}{5 - X}

f (x) = \frac{3 x - 4}{d ^{6} - 2 x}

f (x) = (x + 3)^{2} + 4

2.3

What is the inverse of (10)/((t+16)(t+25)) ?
The inverse of (10)/((t+16)(t+25)) is (-41t+sqrt(81t^2+40t))/(2t),(-41t-sqrt(81t^2+40t))/(2t)