What is the inverse of f(x)=(x+3)^2-5 ?

The inverse of f(x)=(x+3)^2-5 is sqrt(x+5)-3,-sqrt(x+5)-3

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inverse of f(x)=(x+3)^2-5

inverse

f (x) = (x + 3)^{2} - 5

x + 5 - 3, - x + 5 - 3

Solution steps

y = (x + 3)^{2} - 5

Replace

x

with

y

x = (y + 3)^{2} - 5

Solve for

y, x = (y + 3)^{2} - 5

x + 5 - 3, - x + 5 - 3

f (x) = \frac{( 5 + x )}{6 - 2 x}

f (x) = \frac{3 x + 1}{- 3 x + 5}

f (x) = (\frac{5 x}{9}) - (\frac{160}{9})

f (x) = 3 - \frac{x}{2}

f (x) = 2 - 5 x - 3 - 2

What is the inverse of f(x)=(x+3)^2-5 ?
The inverse of f(x)=(x+3)^2-5 is sqrt(x+5)-3,-sqrt(x+5)-3