What is the inverse of f(x)=-x^2+3,x>= 0 ?

The inverse of f(x)=-x^2+3,x>= 0 is sqrt(-x+3),-sqrt(-x+3)

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inverse of f(x)=-x^2+3,x>= 0

inverse

f (x) = - x^{2} + 3, x \geq 0

- x + 3, - - x + 3

Solution steps

y = - x^{2} + 3

Replace

x

with

y

x = - y^{2} + 3

Solve for

y, x = - y^{2} + 3

- x + 3, - - x + 3

35

sin (4) x^{4}

f (x) = - 1 - 4 ln (2 - \frac{x}{2})

\frac{- 4 x}{3 - x}

(ln (x))^{4}

What is the inverse of f(x)=-x^2+3,x>= 0 ?
The inverse of f(x)=-x^2+3,x>= 0 is sqrt(-x+3),-sqrt(-x+3)