What is the inverse of f(x)=7(x+4)^2-8 ?

The inverse of f(x)=7(x+4)^2-8 is sqrt((x+8)/7)-4,-sqrt((x+8)/7)-4

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inverse of f(x)=7(x+4)^2-8

inverse

f (x) = 7 (x + 4)^{2} - 8

\frac{x + 8}{7} - 4, - \frac{x + 8}{7} - 4

Solution steps

y = 7 (x + 4)^{2} - 8

Replace

x

with

y

x = 7 (y + 4)^{2} - 8

Solve for

y, x = 7 (y + 4)^{2} - 8

\frac{x + 8}{7} - 4, - \frac{x + 8}{7} - 4

f (x) = 50 - 5 x

f (x) = 30 x^{3} - 2

f (x) = 4 - (\frac{1}{2})^{x - 2}

What is the inverse of f(x)=7(x+4)^2-8 ?
The inverse of f(x)=7(x+4)^2-8 is sqrt((x+8)/7)-4,-sqrt((x+8)/7)-4