What is the inverse of f(x)=x^2+2x-3,x<=-2 ?

The inverse of f(x)=x^2+2x-3,x<=-2 is -1+sqrt(x+4),-sqrt(x+4)-1

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inverse of f(x)=x^2+2x-3,x<=-2

inverse

f (x) = x^{2} + 2 x - 3, x \leq - 2

- 1 + x + 4, - x + 4 - 1

Solution steps

y = x^{2} + 2 x - 3

Replace

x

with

y

x = y^{2} + 2 y - 3

Solve for

y, x = y^{2} + 2 y - 3

- 1 + x + 4, - x + 4 - 1

f (x) = \frac{5 - 12 x}{6 + 10 x}

f (x) = \frac{x + 9}{x - 7}

f (x) = 8 x + 8 + 9

f (x) = f (x) = 2 - x + 6

y = 246000 \cdot (0.97)^{x}

What is the inverse of f(x)=x^2+2x-3,x<=-2 ?
The inverse of f(x)=x^2+2x-3,x<=-2 is -1+sqrt(x+4),-sqrt(x+4)-1