What is the inverse of (s-6)/(s^2-2s+10) ?

The inverse of (s-6)/(s^2-2s+10) is (2s+1+sqrt(-36s^2-20s+1))/(2s),(2s+1-sqrt(-36s^2-20s+1))/(2s)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

inverse of (s-6)/(s^2-2s+10)

inverse

\frac{s - 6}{s ^{2} - 2 s + 10}

\frac{2 s + 1 + - 36 s ^{2} - 20 s + 1}{2 s}, \frac{2 s + 1 - - 36 s ^{2} - 20 s + 1}{2 s}

Solution steps

y = \frac{s - 6}{s ^{2} - 2 s + 10}

Replace

s

with

y

s = \frac{y - 6}{y ^{2} - 2 y + 10}

Solve for

y, s = \frac{y - 6}{y ^{2} - 2 y + 10}

\frac{2 s + 1 + - 36 s ^{2} - 20 s + 1}{2 s}, \frac{2 s + 1 - - 36 s ^{2} - 20 s + 1}{2 s}

f (x) = 1 + (\frac{1}{2})^{x}

\frac{5}{4 + x ^{2}}

f (x) = 3 (2 + x)

g (x) = x \frac{1}{2}

f (x) = \frac{11}{x + 12}

What is the inverse of (s-6)/(s^2-2s+10) ?
The inverse of (s-6)/(s^2-2s+10) is (2s+1+sqrt(-36s^2-20s+1))/(2s),(2s+1-sqrt(-36s^2-20s+1))/(2s)