What is the inverse of f(x)=(x-1)g(x)=sqrt(x-1) ?

The inverse of f(x)=(x-1)g(x)=sqrt(x-1) is x^2+1

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inverse of f(x)=(x-1)g(x)=sqrt(x-1)

inverse

f (x) = (x - 1) g (x) = x - 1

x^{2} + 1

Solution steps

y = x - 1

Replace

x

with

y

x = y - 1

Solve for

y, x = y - 1

x^{2} + 1

\frac{d}{d} \frac{5}{x}

f (x) = 6 + 2 x - 6

h (x) = (x)^{- 1} = x + 5

f (\frac{π}{6})

f (x) = \frac{x - 2}{2 x - 3}

What is the inverse of f(x)=(x-1)g(x)=sqrt(x-1) ?
The inverse of f(x)=(x-1)g(x)=sqrt(x-1) is x^2+1