What is the inverse of f(x)=(x+2)^2+5 ?

The inverse of f(x)=(x+2)^2+5 is sqrt(x-5)-2,-sqrt(x-5)-2

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inverse of f(x)=(x+2)^2+5

inverse

f (x) = (x + 2)^{2} + 5

x - 5 - 2, - x - 5 - 2

Solution steps

y = (x + 2)^{2} + 5

Replace

x

with

y

x = (y + 2)^{2} + 5

Solve for

y, x = (y + 2)^{2} + 5

x - 5 - 2, - x - 5 - 2

f (x) = (x + 2)^{2} + 7

f (x) = 0.26666667

e^{9 \cdot s i n (x)}

f (x) = \frac{x - 16}{13}

What is the inverse of f(x)=(x+2)^2+5 ?
The inverse of f(x)=(x+2)^2+5 is sqrt(x-5)-2,-sqrt(x-5)-2