What is the inverse of f(x)=(x-14)^2,[14,infinity ] ?

The inverse of f(x)=(x-14)^2,[14,infinity ] is sqrt(x)+14,-sqrt(x)+14

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inverse of f(x)=(x-14)^2,[14,infinity ]

inverse

f (x) = (x - 14)^{2}, [14, \infty]

x + 14, - x + 14

Solution steps

y = (x - 14)^{2}

Replace

x

with

y

x = (y - 14)^{2}

Solve for

y, x = (y - 14)^{2}

x + 14, - x + 14

\frac{s ^{2}}{s ^{2} + 1}

f (x) = \frac{- 5 x + 4}{3 x - 1}

f (x) = \frac{5}{2} x - \frac{15}{2}

f (x) = 2 x [x + 3]

h (x) = [(x)]^{2} + 1

What is the inverse of f(x)=(x-14)^2,[14,infinity ] ?
The inverse of f(x)=(x-14)^2,[14,infinity ] is sqrt(x)+14,-sqrt(x)+14