What is the inverse of ln(x^2-3x+2) ?

The inverse of ln(x^2-3x+2) is (3+sqrt(4e^x+1))/2 ,(3-sqrt(4e^x+1))/2

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inverse of ln(x^2-3x+2)

inverse

ln (x^{2} - 3 x + 2)

\frac{3 + 4 e ^{x} + 1}{2}, \frac{3 - 4 e ^{x} + 1}{2}

Solution steps

y = ln (x^{2} - 3 x + 2)

Replace

x

with

y

x = ln (y^{2} - 3 y + 2)

Solve for

y, x = ln (y^{2} - 3 y + 2)

\frac{3 + 4 e ^{x} + 1}{2}, \frac{3 - 4 e ^{x} + 1}{2}

y = 5

y = 7

f (x) = \frac{( 2 x - 3 )}{5}

- \frac{1}{8} 2^{2 x - 1} + 3

f (x) = - 4 - \frac{3}{4} x

What is the inverse of ln(x^2-3x+2) ?
The inverse of ln(x^2-3x+2) is (3+sqrt(4e^x+1))/2 ,(3-sqrt(4e^x+1))/2