What is the inverse of g(x)=-3/4 x^2-1/2 ?

The inverse of g(x)=-3/4 x^2-1/2 is sqrt(-(4x+2)/3),-sqrt(-(4x+2)/3)

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inverse of g(x)=-3/4 x^2-1/2

inverse

g (x) = - \frac{3}{4} x^{2} - \frac{1}{2}

- \frac{4 x + 2}{3}, - - \frac{4 x + 2}{3}

Solution steps

y = - \frac{3}{4} x^{2} - \frac{1}{2}

Replace

x

with

y

x = - \frac{3}{4} y^{2} - \frac{1}{2}

Solve for

y, x = - \frac{3}{4} y^{2} - \frac{1}{2}

- \frac{4 x + 2}{3}, - - \frac{4 x + 2}{3}

(x - 1)^{4} + 3, x \geq 1

f (x) = \frac{5 x - 2}{4 x + 7}

f (x) = - 6 x^{5} + 17

\frac{8 x}{x - 2}

f (x) = \frac{( x + 1 )}{2 x - 3}

What is the inverse of g(x)=-3/4 x^2-1/2 ?
The inverse of g(x)=-3/4 x^2-1/2 is sqrt(-(4x+2)/3),-sqrt(-(4x+2)/3)