What is the inverse of (-3x^2-2x+6)/5 ?

The inverse of (-3x^2-2x+6)/5 is -(1+sqrt(-15x+19))/3 ,-(1-sqrt(-15x+19))/3

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inverse of (-3x^2-2x+6)/5

inverse

\frac{- 3 x ^{2} - 2 x + 6}{5}

- \frac{1 + - 15 x + 19}{3}, - \frac{1 - - 15 x + 19}{3}

Solution steps

y = \frac{- 3 x ^{2} - 2 x + 6}{5}

Replace

x

with

y

x = \frac{- 3 y ^{2} - 2 y + 6}{5}

Solve for

y, x = \frac{- 3 y ^{2} - 2 y + 6}{5}

- \frac{1 + - 15 x + 19}{3}, - \frac{1 - - 15 x + 19}{3}

\frac{x - 3}{x ^{2} - 4}

y = lo g_{10} (x + 1)

y = x^{2} + 10

ln (\frac{3 + 2 x ^{2}}{x ^{2} + 1})

f (x) = - 3 + \frac{x - 4}{2}

What is the inverse of (-3x^2-2x+6)/5 ?
The inverse of (-3x^2-2x+6)/5 is -(1+sqrt(-15x+19))/3 ,-(1-sqrt(-15x+19))/3