What is the inverse of f(x)=(x+4)^2-11,x>3 ?

The inverse of f(x)=(x+4)^2-11,x>3 is sqrt(x+11)-4,-sqrt(x+11)-4

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inverse of f(x)=(x+4)^2-11,x>3

inverse

f (x) = (x + 4)^{2} - 11, x > 3

x + 11 - 4, - x + 11 - 4

Solution steps

y = (x + 4)^{2} - 11

Replace

x

with

y

x = (y + 4)^{2} - 11

Solve for

y, x = (y + 4)^{2} - 11

x + 11 - 4, - x + 11 - 4

y = \frac{x ^{2} + 1}{x}

f (x) = \frac{7 ^{x + 6}}{7}

10 - 3 - x

y = \frac{2 x - 1}{x + 1}

What is the inverse of f(x)=(x+4)^2-11,x>3 ?
The inverse of f(x)=(x+4)^2-11,x>3 is sqrt(x+11)-4,-sqrt(x+11)-4