What is the inverse of y= 4/(x^2) ?

The inverse of y= 4/(x^2) is (2sqrt(x))/x ,-(2sqrt(x))/x

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inverse of y= 4/(x^2)

inverse

y = \frac{4}{x ^{2}}

\frac{2 x}{x}, - \frac{2 x}{x}

Solution steps

y = \frac{4}{x ^{2}}

Replace

x

with

y

x = \frac{4}{y ^{2}}

Solve for

y, x = \frac{4}{y ^{2}}

\frac{2 x}{x}, - \frac{2 x}{x}

f (x) = \frac{- x - 14}{5}

f (x) = 200 ln (\frac{400}{500 - x}) + 100

lo g_{2} (2 x) + \frac{5}{2}

y = \frac{t + 1}{t + 2}

f (x) = 4240 + 0.25 (x - 30550)

What is the inverse of y= 4/(x^2) ?
The inverse of y= 4/(x^2) is (2sqrt(x))/x ,-(2sqrt(x))/x