What is the inverse of y= 1/2 (x-4)^2+1 ?

The inverse of y= 1/2 (x-4)^2+1 is sqrt(2x-2)+4,-sqrt(2x-2)+4

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inverse of y= 1/2 (x-4)^2+1

inverse

y = \frac{1}{2} (x - 4)^{2} + 1

2 x - 2 + 4, - 2 x - 2 + 4

Solution steps

y = \frac{1}{2} (x - 4)^{2} + 1

Replace

x

with

y

x = \frac{1}{2} (y - 4)^{2} + 1

Solve for

y, x = \frac{1}{2} (y - 4)^{2} + 1

2 x - 2 + 4, - 2 x - 2 + 4

f (x) = - 3 x^{3} + 4

\frac{x ^{2} - 16}{x ^{2} + 169}

\frac{3}{z - 2}

f (x) = 18500 (0.25 - x)

f (x) = 8 x + 72

What is the inverse of y= 1/2 (x-4)^2+1 ?
The inverse of y= 1/2 (x-4)^2+1 is sqrt(2x-2)+4,-sqrt(2x-2)+4