What is the range of (x+2)/(x-1) ?

The range of (x+2)/(x-1) is f(x) 1

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range of (x+2)/(x-1)

range

\frac{x + 2}{x - 1}

f (x) < 1 or f (x) > 1

Interval Notation

(- \infty, 1) \cup (1, \infty)

Solution steps

The function range is the combined domain of the inverse functions

Find the inverse function(s) of:

\frac{x + 2}{x - 1}

Inverse of

\frac{x + 2}{x - 1} : \frac{2 + x}{x - 1}

\frac{2 + x}{x - 1}

Find the domain of each inverse function

Domain of

\frac{2 + x}{x - 1} : x < 1 or x > 1

Combine the intervals

f (x) < 1 or f (x) > 1

f (x) = \frac{5}{x + 7} + 3

(8, - 3), (4, - 7)

\frac{2 x - 4}{x ^{2} + x - 2}

f (x) = \frac{2 x + 3}{x + 1}

x^{2} - 2 x + 1

What is the range of (x+2)/(x-1) ?
The range of (x+2)/(x-1) is f(x)<1\lor f(x)>1