What is the inverse of f(x)=(x^2+4x-12)/(x^2-9x+14) ?

The inverse of f(x)=(x^2+4x-12)/(x^2-9x+14) is (6+7x)/(x-1)

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inverse of f(x)=(x^2+4x-12)/(x^2-9x+14)

inverse

f (x) = \frac{x ^{2} + 4 x - 12}{x ^{2} - 9 x + 14}

\frac{6 + 7 x}{x - 1}

Solution steps

y = \frac{x ^{2} + 4 x - 12}{x ^{2} - 9 x + 14}

Replace

x

with

y

x = \frac{y ^{2} + 4 y - 12}{y ^{2} - 9 y + 14}

Solve for

y, x = \frac{y ^{2} + 4 y - 12}{y ^{2} - 9 y + 14}

\frac{6 + 7 x}{x - 1}

f (x) = \frac{2 x}{5} - 3

f (x) = 1 - 3 x

4.6

f (x) = 6 - 12

\frac{2 z ^{- 1}}{1 - ( \frac{1}{3} ) ( z ^{- 1} )}

What is the inverse of f(x)=(x^2+4x-12)/(x^2-9x+14) ?
The inverse of f(x)=(x^2+4x-12)/(x^2-9x+14) is (6+7x)/(x-1)