What is the inverse of y=(3-e^{-x})/(3+e^{-x)} ?

The inverse of y=(3-e^{-x})/(3+e^{-x)} is -ln((3-3x)/(x+1))

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inverse of y=(3-e^{-x})/(3+e^{-x)}

inverse

y = \frac{3 - e ^{- x}}{3 + e ^{- x}}

- ln (\frac{3 - 3 x}{x + 1})

Solution steps

y = \frac{3 - e ^{- x}}{3 + e ^{- x}}

Replace

x

with

y

x = \frac{3 - e ^{- y}}{3 + e ^{- y}}

Solve for

y, x = \frac{3 - e ^{- y}}{3 + e ^{- y}}

- ln (\frac{3 - 3 x}{x + 1})

f (x) = \frac{2 x + 4}{x + 5}

f (y) = 4 x - 3

2 lo g_{2} (x - 3)

f (x, p) = 2 \cdot \frac{p}{x}

\frac{+ z}{\frac{z}{( z + 0.4 ) ( z - 0.6 )}}

What is the inverse of y=(3-e^{-x})/(3+e^{-x)} ?
The inverse of y=(3-e^{-x})/(3+e^{-x)} is -ln((3-3x)/(x+1))