What is the inverse of (-2s+6)/(s^2+64) ?

The inverse of (-2s+6)/(s^2+64) is (-1+sqrt(-2s(32s-3)+1))/s ,-(sqrt(-2s(32s-3)+1)+1)/s

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

inverse of (-2s+6)/(s^2+64)

inverse

\frac{- 2 s + 6}{s ^{2} + 64}

\frac{- 1 + - 2 s ( 32 s - 3 ) + 1}{s}, - \frac{- 2 s ( 32 s - 3 ) + 1 + 1}{s}

Solution steps

y = \frac{- 2 s + 6}{s ^{2} + 64}

Replace

s

with

y

s = \frac{- 2 y + 6}{y ^{2} + 64}

Solve for

y, s = \frac{- 2 y + 6}{y ^{2} + 64}

\frac{- 1 + - 2 s ( 32 s - 3 ) + 1}{s}, - \frac{- 2 s ( 32 s - 3 ) + 1 + 1}{s}

f (x) = \frac{5 - 3 x}{2 x + 3}

y = - 200 + 200 x

\frac{1}{ln ( 2 x + 1 )}

f (x) = 2 x + 2 = 3 y

f (x) = \frac{- 6 d ^{2}}{2 d - 5}

What is the inverse of (-2s+6)/(s^2+64) ?
The inverse of (-2s+6)/(s^2+64) is (-1+sqrt(-2s(32s-3)+1))/s ,-(sqrt(-2s(32s-3)+1)+1)/s