What is the inverse of ((6s+25))/(s^2+8s+25) ?

The inverse of ((6s+25))/(s^2+8s+25) is (-4s+3+sqrt(-9s^2+s+9))/s ,(-4s+3-sqrt(-9s^2+s+9))/s

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inverse of ((6s+25))/(s^2+8s+25)

inverse

\frac{( 6 s + 25 )}{s ^{2} + 8 s + 25}

\frac{- 4 s + 3 + - 9 s ^{2} + s + 9}{s}, \frac{- 4 s + 3 - - 9 s ^{2} + s + 9}{s}

Solution steps

y = \frac{6 s + 25}{s ^{2} + 8 s + 25}

Replace

s

with

y

s = \frac{6 y + 25}{y ^{2} + 8 y + 25}

Solve for

y, s = \frac{6 y + 25}{y ^{2} + 8 y + 25}

\frac{- 4 s + 3 + - 9 s ^{2} + s + 9}{s}, \frac{- 4 s + 3 - - 9 s ^{2} + s + 9}{s}

f (x) = lo g_{10} (2. 2^{(x)})

f (x) = x - 2 x

y + 3

f (x) = \frac{3 x - 4}{2 x - x}

f (x) = lo g_{7} (x)

What is the inverse of ((6s+25))/(s^2+8s+25) ?
The inverse of ((6s+25))/(s^2+8s+25) is (-4s+3+sqrt(-9s^2+s+9))/s ,(-4s+3-sqrt(-9s^2+s+9))/s