What is the inverse of f(x)=x^3-1,x> pi/2 ?

The inverse of f(x)=x^3-1,x> pi/2 is cube root of x+1

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inverse of f(x)=x^3-1,x> pi/2

inverse

f (x) = x^{3} - 1, x > \frac{π}{2}

3 x + 1

Solution steps

y = x^{3} - 1

Replace

x

with

y

x = y^{3} - 1

Solve for

y, x = y^{3} - 1

3 x + 1

y = x + 1

f (x) = \frac{( - 4 x - 2 )}{( - 3 x + 2 )}

\frac{x + 6}{x + 2}

f (x) = 3 x^{2} - x + 3

F (x) = 3 2 x + 3

What is the inverse of f(x)=x^3-1,x> pi/2 ?
The inverse of f(x)=x^3-1,x> pi/2 is cube root of x+1