What is the inverse of (s-4)/(s^2-2s+9) ?

The inverse of (s-4)/(s^2-2s+9) is (2s+1+sqrt(-32s^2-12s+1))/(2s),(2s+1-sqrt(-32s^2-12s+1))/(2s)

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inverse of (s-4)/(s^2-2s+9)

inverse

\frac{s - 4}{s ^{2} - 2 s + 9}

\frac{2 s + 1 + - 32 s ^{2} - 12 s + 1}{2 s}, \frac{2 s + 1 - - 32 s ^{2} - 12 s + 1}{2 s}

Solution steps

y = \frac{s - 4}{s ^{2} - 2 s + 9}

Replace

s

with

y

s = \frac{y - 4}{y ^{2} - 2 y + 9}

Solve for

y, s = \frac{y - 4}{y ^{2} - 2 y + 9}

\frac{2 s + 1 + - 32 s ^{2} - 12 s + 1}{2 s}, \frac{2 s + 1 - - 32 s ^{2} - 12 s + 1}{2 s}

f (x) = \frac{5 x}{9 - 7 x}

f (x) = lo g_{10} (3) (x - 1) + 2

y = 1000 \cdot (9000 \cdot x)

y = x^{3} {-, 2 < x < 2}

f (x) = \frac{16 x ^{4} - 8 x}{4 x}

What is the inverse of (s-4)/(s^2-2s+9) ?
The inverse of (s-4)/(s^2-2s+9) is (2s+1+sqrt(-32s^2-12s+1))/(2s),(2s+1-sqrt(-32s^2-12s+1))/(2s)