What is the inverse of 3x^{2/7} ?

The inverse of 3x^{2/7} is (x^{7/2})/(27*3^{1/2)},-(x^{7/2})/(27*3^{1/2)}

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inverse of 3x^{2/7}

inverse

3 x^{\frac{2}{7}}

\frac{x ^{\frac{7}{2}}}{27 \cdot 3 ^{\frac{1}{2}}}, - \frac{x ^{\frac{7}{2}}}{27 \cdot 3 ^{\frac{1}{2}}}

Solution steps

y = 3 x^{\frac{2}{7}}

Replace

x

with

y

x = 3 y^{\frac{2}{7}}

Solve for

y, x = 3 y^{\frac{2}{7}}

\frac{x ^{\frac{7}{2}}}{27 \cdot 3 ^{\frac{1}{2}}}, - \frac{x ^{\frac{7}{2}}}{27 \cdot 3 ^{\frac{1}{2}}}

f (x) = \frac{4 x + 7}{x + 2}

\frac{+ z ( 10 + 5 z )}{( 2 z - 11 )}

f (x) = \frac{( 6 - x )}{( 5 + x )}

f (x) = \frac{1}{4} x + 14

x^{2} - 8 x + 5

What is the inverse of 3x^{2/7} ?
The inverse of 3x^{2/7} is (x^{7/2})/(27*3^{1/2)},-(x^{7/2})/(27*3^{1/2)}