What is the inverse of f(x)=-2(x+1)^2+4 ?

The inverse of f(x)=-2(x+1)^2+4 is sqrt(-(x-4)/2)-1,-sqrt(-(x-4)/2)-1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

inverse of f(x)=-2(x+1)^2+4

inverse

f (x) = - 2 (x + 1)^{2} + 4

- \frac{x - 4}{2} - 1, - - \frac{x - 4}{2} - 1

Solution steps

y = - 2 (x + 1)^{2} + 4

Replace

x

with

y

x = - 2 (y + 1)^{2} + 4

Solve for

y, x = - 2 (y + 1)^{2} + 4

- \frac{x - 4}{2} - 1, - - \frac{x - 4}{2} - 1

f (x) = \frac{5 x - 1}{x + 7}

g (x) = \frac{5}{3 x - 1}

2 e^{- 2 x}

f (x) = \frac{2 x ( x + 3 )}{( x - 2 ) ( x - 5 )}

What is the inverse of f(x)=-2(x+1)^2+4 ?
The inverse of f(x)=-2(x+1)^2+4 is sqrt(-(x-4)/2)-1,-sqrt(-(x-4)/2)-1