What is the inverse of f(x)=3x^2+18x+6 ?

The inverse of f(x)=3x^2+18x+6 is (-18+sqrt(12x+252))/6 ,(-18-sqrt(12x+252))/6

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inverse of f(x)=3x^2+18x+6

inverse

f (x) = 3 x^{2} + 18 x + 6

\frac{- 18 + 12 x + 252}{6}, \frac{- 18 - 12 x + 252}{6}

Solution steps

y = 3 x^{2} + 18 x + 6

Replace

x

with

y

x = 3 y^{2} + 18 y + 6

Solve for

y, x = 3 y^{2} + 18 y + 6

\frac{- 18 + 12 x + 252}{6}, \frac{- 18 - 12 x + 252}{6}

f (x) = 7 x^{9}

3 3 x - 1 + 2

f (x) = \frac{11}{x - 8}

f (x) = 10 z^{- 1}

f (x) = - 5 x + 16

What is the inverse of f(x)=3x^2+18x+6 ?
The inverse of f(x)=3x^2+18x+6 is (-18+sqrt(12x+252))/6 ,(-18-sqrt(12x+252))/6