What is the inverse of (4x^2)/(26x-10) ?

The inverse of (4x^2)/(26x-10) is (13x+sqrt(169x^2-40x))/4 ,(13x-sqrt(169x^2-40x))/4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

inverse of (4x^2)/(26x-10)

inverse

\frac{4 x ^{2}}{26 x - 10}

\frac{13 x + 169 x ^{2} - 40 x}{4}, \frac{13 x - 169 x ^{2} - 40 x}{4}

Solution steps

y = \frac{4 x ^{2}}{26 x - 10}

Replace

x

with

y

x = \frac{4 y ^{2}}{26 y - 10}

Solve for

y, x = \frac{4 y ^{2}}{26 y - 10}

\frac{13 x + 169 x ^{2} - 40 x}{4}, \frac{13 x - 169 x ^{2} - 40 x}{4}

\frac{t - 4}{1 - t}

\frac{3}{1 + x ^{2}}

f (x) = \frac{7 x - 6}{x + 3}

f (x) = \frac{8}{7 + x}

7 e^{x} - 3

What is the inverse of (4x^2)/(26x-10) ?
The inverse of (4x^2)/(26x-10) is (13x+sqrt(169x^2-40x))/4 ,(13x-sqrt(169x^2-40x))/4