What is the inverse of f(x)=(x-7)^2+10 ?

The inverse of f(x)=(x-7)^2+10 is sqrt(x-10)+7,-sqrt(x-10)+7

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inverse of f(x)=(x-7)^2+10

inverse

f (x) = (x - 7)^{2} + 10

x - 10 + 7, - x - 10 + 7

Solution steps

y = (x - 7)^{2} + 10

Replace

x

with

y

x = (y - 7)^{2} + 10

Solve for

y, x = (y - 7)^{2} + 10

x - 10 + 7, - x - 10 + 7

x - 2 + 10

f (x) = x^{2} - 1, 3 \leq x < 5

p (x) = x - 4

What is the inverse of f(x)=(x-7)^2+10 ?
The inverse of f(x)=(x-7)^2+10 is sqrt(x-10)+7,-sqrt(x-10)+7