What is the inverse of f(x)=((x-1))/((2x+7)) ?

The inverse of f(x)=((x-1))/((2x+7)) is (-1-7x)/(2x-1)

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inverse of f(x)=((x-1))/((2x+7))

inverse

f (x) = \frac{( x - 1 )}{( 2 x + 7 )}

\frac{- 1 - 7 x}{2 x - 1}

Solution steps

y = \frac{x - 1}{2 x + 7}

Replace

x

with

y

x = \frac{y - 1}{2 y + 7}

Solve for

y, x = \frac{y - 1}{2 y + 7}

\frac{- 1 - 7 x}{2 x - 1}

f (x) = \frac{2 x + 4}{x - 2}

f (x) = π^{x}

f (x) = \frac{7 x - 6}{x + 4}

- 2 sin (4 x - π)

f (x) = - 5 (- 5 x - 1)^{2}

What is the inverse of f(x)=((x-1))/((2x+7)) ?
The inverse of f(x)=((x-1))/((2x+7)) is (-1-7x)/(2x-1)