What is the inverse of g(x)=(sqrt(x)+4)/(1-sqrt(x)) ?

The inverse of g(x)=(sqrt(x)+4)/(1-sqrt(x)) is (16-8x+x^2)/(1+2x+x^2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

inverse of g(x)=(sqrt(x)+4)/(1-sqrt(x))

inverse

g (x) = \frac{x + 4}{1 - x}

\frac{16 - 8 x + x ^{2}}{1 + 2 x + x ^{2}}

Solution steps

y = \frac{x + 4}{1 - x}

Replace

x

with

y

x = \frac{y + 4}{1 - y}

Solve for

y, x = \frac{y + 4}{1 - y}

\frac{16 - 8 x + x ^{2}}{1 + 2 x + x ^{2}}

f (x) = (\frac{- ( cos ( π \cdot y ) - 1 )}{2})

- 4 x - 3

- 4 x - 2

y = 11.25 x + 90

f (x) = \frac{( x \cdot x - 2 )}{( x - 1 ) \cdot x}

What is the inverse of g(x)=(sqrt(x)+4)/(1-sqrt(x)) ?
The inverse of g(x)=(sqrt(x)+4)/(1-sqrt(x)) is (16-8x+x^2)/(1+2x+x^2)