What is the inverse of y=-(x+1)^2-2 ?

The inverse of y=-(x+1)^2-2 is sqrt(-x-2)-1,-sqrt(-x-2)-1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

inverse of y=-(x+1)^2-2

inverse

y = - (x + 1)^{2} - 2

- x - 2 - 1, - - x - 2 - 1

Solution steps

y = - (x + 1)^{2} - 2

Replace

x

with

y

x = - (y + 1)^{2} - 2

Solve for

y, x = - (y + 1)^{2} - 2

- x - 2 - 1, - - x - 2 - 1

f (x) = 7 + e^{2 x}

7 x - 4

y = \frac{2}{3} x + (- 6)

f (x) = \frac{1}{x + 4}

f (x) = (x + \frac{3}{2})^{2} - \frac{37}{4}

What is the inverse of y=-(x+1)^2-2 ?
The inverse of y=-(x+1)^2-2 is sqrt(-x-2)-1,-sqrt(-x-2)-1