What is the inverse of f(x)=-1/2 (1/2)^x+7 ?

The inverse of f(x)=-1/2 (1/2)^x+7 is -(ln(7-x))/(ln(2))-1

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inverse of f(x)=-1/2 (1/2)^x+7

inverse

f (x) = - \frac{1}{2} (\frac{1}{2})^{x} + 7

- \frac{ln ( 7 - x )}{ln ( 2 )} - 1

Solution steps

y = - \frac{1}{2} (\frac{1}{2})^{x} + 7

Replace

x

with

y

x = - \frac{1}{2} (\frac{1}{2})^{y} + 7

Solve for

y, x = - \frac{1}{2} (\frac{1}{2})^{y} + 7

- \frac{ln ( 7 - x )}{ln ( 2 )} - 1

f (x) = arccos (e) (e^{3 x})

\frac{4}{a - 7}

- \frac{( 2 x + 3 )}{x} - 5

f (x) = (ln (x))^{6}

- \frac{2}{x + 1} + 4

What is the inverse of f(x)=-1/2 (1/2)^x+7 ?
The inverse of f(x)=-1/2 (1/2)^x+7 is -(ln(7-x))/(ln(2))-1