What is the inverse of f(x)=((x+1))/((2x-3)) ?

The inverse of f(x)=((x+1))/((2x-3)) is (1+3x)/(2x-1)

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inverse of f(x)=((x+1))/((2x-3))

inverse

f (x) = \frac{( x + 1 )}{( 2 x - 3 )}

\frac{1 + 3 x}{2 x - 1}

Solution steps

y = \frac{x + 1}{2 x - 3}

Replace

x

with

y

x = \frac{y + 1}{2 y - 3}

Solve for

y, x = \frac{y + 1}{2 y - 3}

\frac{1 + 3 x}{2 x - 1}

f (x) = 5 x^{4} + 2 x^{2}

\frac{6 x}{5} + 7

P (n) = 0.2 n + 5.3

f (x) = 11 x - 19

f (x) = 3 x + 2

What is the inverse of f(x)=((x+1))/((2x-3)) ?
The inverse of f(x)=((x+1))/((2x-3)) is (1+3x)/(2x-1)