What is the inverse of f(x)=(x-8)^2+16 ?

The inverse of f(x)=(x-8)^2+16 is sqrt(x-16)+8,-sqrt(x-16)+8

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inverse of f(x)=(x-8)^2+16

inverse

f (x) = (x - 8)^{2} + 16

x - 16 + 8, - x - 16 + 8

Solution steps

y = (x - 8)^{2} + 16

Replace

x

with

y

x = (y - 8)^{2} + 16

Solve for

y, x = (y - 8)^{2} + 16

x - 16 + 8, - x - 16 + 8

\frac{1}{1 + \frac{3}{4} z ^{- 1}}

f (x) = \frac{1}{6} x + \frac{5}{2}

y = \frac{3 x - 8}{x + 9}

\frac{3}{2} (x + 4)

f (x) = f (x) = (x - 3)^{2} + 2

What is the inverse of f(x)=(x-8)^2+16 ?
The inverse of f(x)=(x-8)^2+16 is sqrt(x-16)+8,-sqrt(x-16)+8