What is the inverse of y=((2x-4))/((3x+5)) ?

The inverse of y=((2x-4))/((3x+5)) is (-4-5x)/(3x-2)

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inverse of y=((2x-4))/((3x+5))

inverse

y = \frac{( 2 x - 4 )}{( 3 x + 5 )}

\frac{- 4 - 5 x}{3 x - 2}

Solution steps

y = \frac{2 x - 4}{3 x + 5}

Replace

x

with

y

x = \frac{2 y - 4}{3 y + 5}

Solve for

y, x = \frac{2 y - 4}{3 y + 5}

\frac{- 4 - 5 x}{3 x - 2}

f (x) = \frac{x}{1}

\frac{3 x - 5}{7 x + 1}

f (x) = \frac{5 - 7 \cdot 6}{2}

y = \frac{x ^{2}}{3}

What is the inverse of y=((2x-4))/((3x+5)) ?
The inverse of y=((2x-4))/((3x+5)) is (-4-5x)/(3x-2)