What is the inverse of (10000)/(100+900e^{-t)} ?

The inverse of (10000)/(100+900e^{-t)} is -ln((100-t)/(9t))

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inverse of (10000)/(100+900e^{-t)}

inverse

\frac{10000}{100 + 900 e ^{- t}}

- ln (\frac{100 - t}{9 t})

Solution steps

y = \frac{10000}{100 + 900 e ^{- t}}

Replace

t

with

y

t = \frac{10000}{100 + 900 e ^{- y}}

Solve for

y, t = \frac{10000}{100 + 900 e ^{- y}}

- ln (\frac{100 - t}{9 t})

g (x) = 2 3 x - 1

1 0^{2}

35 (3)^{2835}

36 lo g_{6} (5)

y = \frac{5 x - 2}{4 x + 3}

What is the inverse of (10000)/(100+900e^{-t)} ?
The inverse of (10000)/(100+900e^{-t)} is -ln((100-t)/(9t))