What is the inverse of f(x)=9x^2+7 ?

The inverse of f(x)=9x^2+7 is (sqrt(x-7))/3 ,-(sqrt(x-7))/3

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inverse of f(x)=9x^2+7

inverse

f (x) = 9 x^{2} + 7

\frac{x - 7}{3}, - \frac{x - 7}{3}

Solution steps

y = 9 x^{2} + 7

Replace

x

with

y

x = 9 y^{2} + 7

Solve for

y, x = 9 y^{2} + 7

\frac{x - 7}{3}, - \frac{x - 7}{3}

f (x) = x^{6} + 16

f (x) = \frac{x - 2}{4 x + 9}

f (x) = 19 \cdot x - 53

f (x) = 2 x^{(3)} - 1

8 x + 9 x^{2} + 1 + 1

What is the inverse of f(x)=9x^2+7 ?
The inverse of f(x)=9x^2+7 is (sqrt(x-7))/3 ,-(sqrt(x-7))/3