What is the inverse of (x^2-x-12)/(x^2-9) ?

The inverse of (x^2-x-12)/(x^2-9) is (-4+3x)/(x-1)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

inverse of (x^2-x-12)/(x^2-9)

inverse

\frac{x ^{2} - x - 12}{x ^{2} - 9}

\frac{- 4 + 3 x}{x - 1}

Solution steps

y = \frac{x ^{2} - x - 12}{x ^{2} - 9}

Replace

x

with

y

x = \frac{y ^{2} - y - 12}{y ^{2} - 9}

Solve for

y, x = \frac{y ^{2} - y - 12}{y ^{2} - 9}

\frac{- 4 + 3 x}{x - 1}

f (x) = x^{- \frac{1}{2}}

x + 7 - 1

y = \frac{5 x ^{3} - 2}{x ^{3} + 1}

f (x) = - x^{2} - 3 x + 4

100 - x^{2}

What is the inverse of (x^2-x-12)/(x^2-9) ?
The inverse of (x^2-x-12)/(x^2-9) is (-4+3x)/(x-1)