What is the inverse of-1/3 (x-2)^2-4 ?

The inverse of-1/3 (x-2)^2-4 is sqrt(-3x-12)+2,-sqrt(-3x-12)+2

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inverse of-1/3 (x-2)^2-4

inverse

- \frac{1}{3} (x - 2)^{2} - 4

- 3 x - 12 + 2, - - 3 x - 12 + 2

Solution steps

y = - \frac{1}{3} (x - 2)^{2} - 4

Replace

x

with

y

x = - \frac{1}{3} (y - 2)^{2} - 4

Solve for

y, x = - \frac{1}{3} (y - 2)^{2} - 4

- 3 x - 12 + 2, - - 3 x - 12 + 2

f (x) = 2 x + 4 - 1

f (x) = (x + 3) 4

f (x) = \frac{7}{3 x - 2}

1 - 2

\frac{1}{2} lo g_{10} (3 x)

What is the inverse of-1/3 (x-2)^2-4 ?
The inverse of-1/3 (x-2)^2-4 is sqrt(-3x-12)+2,-sqrt(-3x-12)+2