What is the inverse of f(x)=2(x-1)^2-4 ?

The inverse of f(x)=2(x-1)^2-4 is sqrt((x+4)/2)+1,-sqrt((x+4)/2)+1

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inverse of f(x)=2(x-1)^2-4

inverse

f (x) = 2 (x - 1)^{2} - 4

\frac{x + 4}{2} + 1, - \frac{x + 4}{2} + 1

Solution steps

y = 2 (x - 1)^{2} - 4

Replace

x

with

y

x = 2 (y - 1)^{2} - 4

Solve for

y, x = 2 (y - 1)^{2} - 4

\frac{x + 4}{2} + 1, - \frac{x + 4}{2} + 1

(x + 3)^{2} - 4

1.1

1.4

8 cos (π^{2} x - π^{4}) - 3

f (x) = (x + 5)^{\frac{7}{3}}

What is the inverse of f(x)=2(x-1)^2-4 ?
The inverse of f(x)=2(x-1)^2-4 is sqrt((x+4)/2)+1,-sqrt((x+4)/2)+1