What is the inverse of f(x)=x^4+5,x>= 0 ?

The inverse of f(x)=x^4+5,x>= 0 is \sqrt[4]{x-5},-\sqrt[4]{x-5}

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inverse of f(x)=x^4+5,x>= 0

inverse

f (x) = x^{4} + 5, x \geq 0

Solution steps

y = x^{4} + 5

Replace

x

with

y

x = y^{4} + 5

Solve for

y, x = y^{4} + 5

f (x) = \frac{8 - 6 x}{3 - 4 x}

y = \frac{e ^{x}}{( e ^{x} + 1 )}

f (x) = 0.01327 x + 0.5747

f (t) = 12.8 - 4 t

f (x) = \frac{4 x + 3}{5 x - 5}

What is the inverse of f(x)=x^4+5,x>= 0 ?
The inverse of f(x)=x^4+5,x>= 0 is \sqrt[4]{x-5},-\sqrt[4]{x-5}