What is the inverse of f(x)=((1+3x))/((3-7x)) ?

The inverse of f(x)=((1+3x))/((3-7x)) is -(1-3x)/(3+7x)

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inverse of f(x)=((1+3x))/((3-7x))

inverse

f (x) = \frac{( 1 + 3 x )}{( 3 - 7 x )}

- \frac{1 - 3 x}{3 + 7 x}

Solution steps

y = \frac{1 + 3 x}{3 - 7 x}

Replace

x

with

y

x = \frac{1 + 3 y}{3 - 7 y}

Solve for

y, x = \frac{1 + 3 y}{3 - 7 y}

- \frac{1 - 3 x}{3 + 7 x}

\frac{3}{x + 9}

2 x^{4}

f (x) = 4^{l o g_{4} (3)}

\frac{3}{x + 8}

What is the inverse of f(x)=((1+3x))/((3-7x)) ?
The inverse of f(x)=((1+3x))/((3-7x)) is -(1-3x)/(3+7x)