What is the inverse of e^{-(x^4)/2} ?

The inverse of e^{-(x^4)/2} is 2^{1/4}(-ln(x))^{1/4},-2^{1/4}(-ln(x))^{1/4}

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inverse of e^{-(x^4)/2}

inverse

e^{- \frac{x ^{4}}{2}}

2^{\frac{1}{4}} (- ln (x))^{\frac{1}{4}}, - 2^{\frac{1}{4}} (- ln (x))^{\frac{1}{4}}

Solution steps

y = e^{- \frac{x ^{4}}{2}}

Replace

x

with

y

x = e^{- \frac{y ^{4}}{2}}

Solve for

y, x = e^{- \frac{y ^{4}}{2}}

2^{\frac{1}{4}} (- ln (x))^{\frac{1}{4}}, - 2^{\frac{1}{4}} (- ln (x))^{\frac{1}{4}}

f (x) = (- 1, 2), (4, 1)

f (x) = 5 - x + 6

f (x) = \frac{11}{x + 2}

\frac{1}{2 y}

1 - e^{- \frac{x}{a}}

What is the inverse of e^{-(x^4)/2} ?
The inverse of e^{-(x^4)/2} is 2^{1/4}(-ln(x))^{1/4},-2^{1/4}(-ln(x))^{1/4}