What is the inverse of x^{(1/5)}-2 ?

The inverse of x^{(1/5)}-2 is x^5+10x^4+40x^3+80x^2+80x+32

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inverse of x^{(1/5)}-2

inverse

x^{(\frac{1}{5})} - 2

x^{5} + 10 x^{4} + 40 x^{3} + 80 x^{2} + 80 x + 32

Solution steps

y = x^{\frac{1}{5}} - 2

Replace

x

with

y

x = y^{\frac{1}{5}} - 2

Solve for

y, x = y^{\frac{1}{5}} - 2

x^{5} + 10 x^{4} + 40 x^{3} + 80 x^{2} + 80 x + 32

f (x) = 2 x (1 - x)

0.9

Y (x) = 1.2501 x + 14.78

1 - 2 x

f (x) = (\frac{1}{2})^{x - 3}

What is the inverse of x^{(1/5)}-2 ?
The inverse of x^{(1/5)}-2 is x^5+10x^4+40x^3+80x^2+80x+32