What is the inverse of f(x)=sqrt(23-x^2) ?

The inverse of f(x)=sqrt(23-x^2) is sqrt(-x^2+23),-sqrt(-x^2+23)

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inverse of f(x)=sqrt(23-x^2)

inverse

f (x) = 23 - x^{2}

- x^{2} + 23, - - x^{2} + 23

Solution steps

y = 23 - x^{2}

Replace

x

with

y

x = 23 - y^{2}

Solve for

y, x = 23 - y^{2}

- x^{2} + 23, - - x^{2} + 23

f (x) = (x^{3} - 3)^{\frac{1}{3}} - 1

f (x) = (8 - x) (x + 2)

- \frac{3 x}{x ^{2} - 4}

f (x) = \frac{( 6 x - x ^{2} )}{30}

f (x) = 3.09 x^{2} - 28.27 x + 78.16

What is the inverse of f(x)=sqrt(23-x^2) ?
The inverse of f(x)=sqrt(23-x^2) is sqrt(-x^2+23),-sqrt(-x^2+23)