What is the domain of g(x)=sqrt(x^2-4x) ?

The domain of g(x)=sqrt(x^2-4x) is x = 4

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domain of g(x)=sqrt(x^2-4x)

domain

g (x) = x^{2} - 4 x

x \leq 0 or x \geq 4

Interval Notation

(- \infty, 0] \cup [4, \infty)

Solution steps

Find non-negative values for radicals:

x \leq 0 or x \geq 4

The function domain

x \leq 0 or x \geq 4

f (x) = 6 x^{2} + 500 x + 8000

f (x) = lo g_{2} (\frac{2}{3} x - 4)

f (x) = lo g_{2} (x^{2} - 6 x + 8)

f (x) = 10 - 2 x + 3 x - 1

f (x) = x + 3 - \frac{1 - x}{x}

What is the domain of g(x)=sqrt(x^2-4x) ?
The domain of g(x)=sqrt(x^2-4x) is x<= 0\lor x>= 4