What is the domain of f(x)=((x^2+16))/((x^2-9)) ?

The domain of f(x)=((x^2+16))/((x^2-9)) is x 3

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domain of f(x)=((x^2+16))/((x^2-9))

domain

f (x) = \frac{( x ^{2} + 16 )}{( x ^{2} - 9 )}

x < - 3 or - 3 < x < 3 or x > 3

Interval Notation

(- \infty, - 3) \cup (- 3, 3) \cup (3, \infty)

Solution steps

Find undefined (singularity) points:

x = 3, x = - 3

The function domain

x < - 3 or - 3 < x < 3 or x > 3

f (x) = \frac{5 - x}{- 4 x + 8}

f (x) = \frac{5 x + 2}{x + 1}

f (x) = lo g_{4} (2 - x)

f (x) = \frac{x ^{2} + 3 x}{x ^{2} - 16}

f (x) = x^{4} - 8 x^{2} + a

What is the domain of f(x)=((x^2+16))/((x^2-9)) ?
The domain of f(x)=((x^2+16))/((x^2-9)) is x<-3\lor-3<x<3\lor x>3