What is the domain of f(x)=sqrt(x+a) ?

The domain of f(x)=sqrt(x+a) is x>=-a

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domain of f(x)=sqrt(x+a)

domain

f (x) = x + a

x \geq - a

Solution steps

Find non-negative values for radicals:

x \geq - a

The function domain

x \geq - a

- 5 x - 10

y = \frac{x - 5}{x ^{2} - 4 x}

5 - 3 x

f (x) = \frac{2}{3} (x - 2)^{2} - 5

f (x) = - \frac{2}{5} x + 6, x \neq = 10